How can one solve equations like this? $\displaystyle (x+1)(tanx) = -1$
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With a numerical method - I'd write the equation as $\displaystyle f(x) = (x+1)\tan(x) + 1 =0$ and look for where f(x) changes sign.
Originally Posted by zhangvict How can one solve equations like this? $\displaystyle (x+1)(tanx) = -1$ Using CAS technology or applying a numerical method or using a graphical approach.
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