Parallel and intersective lines solve for the intersections

**chicapsy** · July 31st 2011, 12:22 PM

I'm stuck on this question, would appreciate any help trying to figure this out:

Q)Two parallel lines $y = 2x + 2$ and $y = 2x - 2$ are crossed by a third line. Determine the coefficients of the third line $y = ax + b$ such that the x-coordinate of the intersection of the two lines $y = ax + b$ and $y = 2x - 2$ is twice as much as that of the intersection of the two lines $y = ax + b$ and $y = 2x + 2$ ; and the y-coordinate of the intersection of the two lines $y = ax + b$ and $y = 2x + 2$ is twice as much as that of the intersection of the two lines $y = ax + b$ and $y = 2x - 2$ .
Calculate the coordinates of the two intersections.

Parallel and intersective lines solve for the intersections-graph6.png

I would appreciate any help on this.

**FernandoRevilla** · August 1st 2011, 01:31 AM

Solving $\begin{Bmatrix} y=ax+b\\y=2x+2\end{matrix}$ you'll obtain $x_1=\frac{2-b}{a-2},\;y_1=\frac{2(a-b)}{a-2}$ .

Solving $\begin{Bmatrix} y=ax+b\\y=2x-2\end{matrix}$ you'll obtain $x_2=\frac{b+2}{2-a},\;y_2=\frac{2(a+b)}{2-a}$ .

Now, using $x_2=2x_1,\;y_1=2y_2$ we get a $2\times 2$ linear system. Find $a$ and $b$ .

**chicapsy** · August 4th 2011, 05:41 PM

Thank you.

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