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Math Help - Solving equations?

  1. #1
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    Solving equations?

    I have an equation;

    7 = 2
    3+a a - 2

    can I solve it this way?

    6a + 2a = 8a
    7a - 14 7a -14

    = a - 14

    The method I have used is to cross multiply, but I am unsure?
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  2. #2
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    Re: Solving equations?

    Quote Originally Posted by David Green View Post
    I have an equation;

    7 = 2
    3+a a - 2
    You can say  \frac{7}{3+a}=\frac{2}{a-2}
     \\ 7a-14 =6+2a.

    Now solve for a .
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  3. #3
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    Re: Solving equations?

    Quote Originally Posted by Plato View Post
    You can say  \frac{7}{3+a}=\frac{2}{a-2}
     \\ 7a-14 =6+2a.

    Now solve for a .
    Does that mean that now there is two (a) I have to factor one out?
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  4. #4
    Super Member TheChaz's Avatar
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    Re: Solving equations?

    Quote Originally Posted by David Green View Post
    Does that mean that now there is two (a) I have to factor one out?
    No, this is a linear equation with variables on both sides. You need the two terms with "a" on one side, and everything else on the other side.
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  5. #5
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    Re: Solving equations?

    Quote Originally Posted by David Green View Post
    Does that mean that now there is two (a) I have to factor one out?
    I don't even know what that question means, much less how to answer it.
    What level are you on?
    What are you studying?
    Can you solve 7a-14=6+2a for a~?
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  6. #6
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    Re: Solving equations?

    Quote Originally Posted by Plato View Post
    I don't even know what that question means, much less how to answer it.
    What level are you on?
    What are you studying?
    Can you solve 7a-14=6+2a for a~?
    I am only a beginner

    Introduction to maths

    a(7 - 14)(6 + 2) ???

    7a - 14 = 6 + 2a
    7a - 2a = 6 + 14
    5a = 20
    a = 4

    how am I doing!
    Last edited by David Green; July 30th 2011 at 11:23 AM. Reason: Different idea to the solution
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  7. #7
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    Re: Solving equations?

    Quote Originally Posted by David Green View Post
    I am only a beginner

    Introduction to maths
    \begin{align*}  \frac{7}{3+a}&=\frac{2}{a-2} \\  7a-14 &=6+2a\\ 5a&=20\text{ subtract 2a and add 14} \\ a&=4\end{align*}
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  8. #8
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    Re: Solving equations?

    Quote Originally Posted by Plato View Post
    \begin{align*}  \frac{7}{3+a}&=\frac{2}{a-2} \\  7a-14 &=6+2a\\ 5a&=20\text{ subtract 2a and add 14} \\ a&=4\end{align*}
    Thank you, so I did get it right with a little help, after all "every little helps"
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