Hi everyone, I'm having difficulty on a problem. Please just don't answer it, break it down in steps for me. The finals are 4 days from now. Get back at me ASAP. Thanks. 3x@Sup{3}-24 or 3x^3-24 ( Three "X" to the 3rd, minus 24)
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$\displaystyle \displaystyle 3x^3-24$ The common factor here is 3 so $\displaystyle \displaystyle 3(x^3-8) =3(x^3-2^3) $ Now apply $\displaystyle \displaystyle a^3-b^3 = (a-b)(a^2+ab+b^2)$ to the expression inside the brackets.
Hey, how do you do that? The fonts and such. Anyway, it's (x-2)(x^2+2x+8) ?
Originally Posted by HellBunny Hey, how do you do that? The fonts and such. Anyway, it's (x-2)(x^2+2x+8) ? Times 3, of course!
Originally Posted by HellBunny Hey, how do you do that? The fonts and such. Anyway, it's (x-2)(x^2+2x+8) ? Use the LaTeX feature of this forum. [tex] (x-2)(x^2+2x+8)[/tex] gives $\displaystyle (x-2)(x^2+2x+8)$.
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