Hi everyone, I'm having difficulty on a problem. Please just don't answer it, break it down in steps for me. The finals are 4 days from now. Get back at me ASAP. Thanks.

3x@Sup{3}-24 or 3x^3-24 ( Three "X" to the 3rd, minus 24)

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- Jul 29th 2011, 02:05 PMHellBunnyFactoring Homework
Hi everyone, I'm having difficulty on a problem. Please just don't answer it, break it down in steps for me. The finals are 4 days from now. Get back at me ASAP. Thanks.

3x@Sup{3}-24 or 3x^3-24 ( Three "X" to the 3rd, minus 24) - Jul 29th 2011, 02:11 PMpickslidesRe: Factoring Homework
$\displaystyle \displaystyle 3x^3-24$

The common factor here is 3 so

$\displaystyle \displaystyle 3(x^3-8) =3(x^3-2^3) $

Now apply $\displaystyle \displaystyle a^3-b^3 = (a-b)(a^2+ab+b^2)$ to the expression inside the brackets. - Jul 29th 2011, 02:55 PMHellBunnyRe: Factoring Homework
Hey, how do you do that? The fonts and such. Anyway, it's (x-2)(x^2+2x+8) ?

- Jul 29th 2011, 02:57 PMSammySRe: Factoring Homework
- Jul 29th 2011, 03:03 PMPlatoRe: Factoring Homework