# Factoring Homework

• Jul 29th 2011, 02:05 PM
HellBunny
Factoring Homework
Hi everyone, I'm having difficulty on a problem. Please just don't answer it, break it down in steps for me. The finals are 4 days from now. Get back at me ASAP. Thanks.

3x@Sup{3}-24 or 3x^3-24 ( Three "X" to the 3rd, minus 24)
• Jul 29th 2011, 02:11 PM
pickslides
Re: Factoring Homework
\$\displaystyle \displaystyle 3x^3-24\$

The common factor here is 3 so

\$\displaystyle \displaystyle 3(x^3-8) =3(x^3-2^3) \$

Now apply \$\displaystyle \displaystyle a^3-b^3 = (a-b)(a^2+ab+b^2)\$ to the expression inside the brackets.
• Jul 29th 2011, 02:55 PM
HellBunny
Re: Factoring Homework
Hey, how do you do that? The fonts and such. Anyway, it's (x-2)(x^2+2x+8) ?
• Jul 29th 2011, 02:57 PM
SammyS
Re: Factoring Homework
Quote:

Originally Posted by HellBunny
Hey, how do you do that? The fonts and such. Anyway, it's (x-2)(x^2+2x+8) ?

Times 3, of course!
• Jul 29th 2011, 03:03 PM
Plato
Re: Factoring Homework
Quote:

Originally Posted by HellBunny
Hey, how do you do that? The fonts and such. Anyway, it's (x-2)(x^2+2x+8) ?

Use the LaTeX feature of this forum.
[tex] (x-2)(x^2+2x+8)[/tex] gives \$\displaystyle (x-2)(x^2+2x+8)\$.