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Math Help - Solving Quadratic Equation Using Box Factoring

  1. #1
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    Question Solving Quadratic Equation Using Box Factoring

    f(x)=6x^2+9x-6

    Where does this function intersect the x-axis (i.e. what are the roots or zeroes of f(x))?

    Solve by factoring using the Box Method. When I use the method that is shown on this website Factoring Quadratics: The Hard Case for this particular problem I end up with this as my factored down version of the equation.
    (6x-3)(3x+6)
    But that is wrong because I would end up with 18x^2 instead of 6x^2.

    My question is that does using the method on that website to factor down a quadratic work for this equation? If so, could someone tell me what I'm doing wrong.

    Solving Quadratic Equation Using Box Factoring-quad-problem-.jpg







    Thanks
    Last edited by nordqvist11; July 28th 2011 at 11:17 PM.
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  2. #2
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    Re: Solving Quadratic Equation Using Box Factoring

    Quote Originally Posted by nordqvist11 View Post
    f(x)=6x^2+9x-6
    Well, first divide by 3; so you get this equation:
    2x^2 + 3x - 2 = 0
    Easy to factor: (x - 2)(2x + 1)
    Now go "box" that...whatever that means
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  3. #3
    MHF Contributor Siron's Avatar
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    Re: Solving Quadratic Equation Using Box Factoring

    Are you also able to use other methods? ...
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