How to solve this question greatest_integer(x^2) = greatest_integer(x+2) ?
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You are after the largest solution to this which is also an integer? If so solve $\displaystyle \displaystyle x^2-x-2 = 0$
No, I need all the possible values of x ( for which the eqn holds true)
Greatest_Integer here means the "Greatest Integer Function" ( i dont know how to express it in its form in the forum)
Originally Posted by anshulbshah No, I need all the possible values of x ( for which the eqn holds true) Like this? $\displaystyle \displaystyle x^2 = x+2$ $\displaystyle \displaystyle x^2-x-2 = 0$ $\displaystyle \displaystyle (x-2)(x+1) = 0$ Now use the null factor law.
Originally Posted by pickslides Like this? $\displaystyle \displaystyle x^2 = x+2$ $\displaystyle \displaystyle x^2-x-2 = 0$ $\displaystyle \displaystyle (x-2)(x+1) = 0$ Now use the null factor law. The two solutions that result from pickslides's post are integers, so the greatest integer function will not change them. Now, investigate values of x very nearby these two solutions to see if they will work.
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