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A printer has ink that is 8% cobalt blue color and ink that is 22% cobalt blue color. How many ounce of each ink are needed to make 64 ounces of ink that is 15% cobalt blue color?
I am getting .08x+14.08-22x=9.6
-14.08 -14.08
-21.92x=-4.48
divide -21.92 x= A Nasty Decimal that doesnt make make it right......
1. Let x denote the amount of the 8%-ink and y the amount of the 22%-ink. Convert the percentasges into decimal fractions. Then you know:Quote:
Originally Posted by maes0732
2. Solve for x and y. I've got x = 32 and y = 32.
Ok i will try that out. The way our teacher explained the problems was different. He made us put them in like a table and one ink is obviously X and then the other ink is the 64 ounces to start with so 64-X, but i will give that method a try on a few.
It's better to understand the problem/solution than to imitate the teacher...Quote:
Originally Posted by maes0732
You have the best solution for the problem by earboth. But the way your want to do it as below (some times lower grades teacher don't teach system of linear equations)
Consider X ounces of 8% cobalt, (64 - x) ounces of 22% cobalt are mixed to get 64 ounces of 15% cobalt
Let's write an equation using the above values
8x + 22(64 - x) = 15*64
8x + 1408 - 22x = 960
-14x = 960 - 1408
-14x = -448
x = 32
So, 32 ounces of 8% cobalt, (64 - 32)=32 ounces of 22% cobalt ink is needed.
z = (ax + by) / (a + b)Code:a @ x
b @ y
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(a+b) @ z