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Math Help - Factoring a quadratic equation

  1. #16
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    Re: Factoring a quadratic equation

    Quote Originally Posted by Siron View Post
    Ok, then what you wright is good enough.
    Thanks Siron, much appreciated, everything I am doing is a new learning curve for me.

    I have a new question.

    A parabola is U shaped. My understanding is that this U shape is +
    The parabola has axis of symmetry x = 0
    The parabola has y intercept (0, - 2)
    The points (2, 0) lies on the parabola

    I am asked to find the equation, which I think I got it right here;

    y = 1/2 x^2 - 2
    y = 1/2 x 4 - 2
    y = 0

    How am I doing?
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  2. #17
    MHF Contributor Siron's Avatar
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    Re: Factoring a quadratic equation

    y=\frac{1}{2}x^2-2 looks good.
    Check:
    Does the parabola goes through the points (0,-2) and (2,0): yes!
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  3. #18
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    Re: Factoring a quadratic equation

    Quote Originally Posted by Siron View Post
    y=\frac{1}{2}x^2-2 looks good.
    Check:
    Does the parabola goes through the points (0,-2) and (2,0): yes!
    I have only scetched it by hand, the parabola goes through 2 and - 2, but I am not understanding y = 0 at the moment, x = 0 and y = 0 not fully understood at the moment?

    please explain it if you can?
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  4. #19
    MHF Contributor Siron's Avatar
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    Re: Factoring a quadratic equation

    Okay, for example. Can you determine where the point (0,2) lies ...? On the x-axis? On the y-axis? Why? ...
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  5. #20
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    Re: Factoring a quadratic equation

    Quote Originally Posted by Siron View Post
    Okay, for example. Can you determine where the point (0,2) lies ...? On the x-axis? On the y-axis? Why? ...
    Not to sure what you mean?

    (0, 2) means 0 = x axis and 2 = y axis, I don't understand anymore at the moment?
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  6. #21
    MHF Contributor Siron's Avatar
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    Re: Factoring a quadratic equation

    Okay, 0 we call the x-coordinate and 2 we call the y-coordinate. Can you be more clear about what you don't understand about x=0, y=0, ...
    The (straight) lines:
    x=0: y-axis
    y=0: x-axis
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  7. #22
    MHF Contributor Siron's Avatar
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    Re: Factoring a quadratic equation

    @David:

    Do you understand it now? Or? ...
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  8. #23
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    Re: Factoring a quadratic equation

    we did not talk about it. because its very long question. sorry.
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  9. #24
    MHF Contributor Siron's Avatar
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    Re: Factoring a quadratic equation

    Quote Originally Posted by grouponclonescript View Post
    we did not talk about it. because its very long question. sorry.
    What do you mean? ...
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  10. #25
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    Re: Factoring a quadratic equation

    Quote Originally Posted by Siron View Post
    @David:

    Do you understand it now? Or? ...
    Siron, I will need to read up and ask questions I think?

    I am not sure how to interpret what is being said, suppose I had a graph y = x^2 - 3x - 10, then suppose that the graph is a + parabola, y is the intercept where it crosses or touches the y axis, but that is it is a value of y when x = 0, but then the x intercepts are - 2, 5, y intercept is - 10.

    So the graph is such that the parabola is drawn from the second quadrant down crosses the x axis at -2 then passes through the third quadrant then crosses the y axis at - 10, then turns and goes up through the fourth quadrant cutting the x axis at 5, then entering the first quadrant to finish.

    Thats a lot of information to try and understand how x = 0 and y = 0, I don't understand how they relate together?
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