Could someone please help me with this? ((a^4)b)/(c^2)^^-1/2 Thank you!
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Not much you can do from there... $\displaystyle \left(\frac{a^4b}{c^2}\right)^{-1/2}$ Is this thing you wanna reduce?
Yes, I am sorry I do not know how to use tags. I tried to take away the fractions by multiplying by a^2 and c, but I couldn't get the right answer.
See the LaTeX Tutorial Now, we have that $\displaystyle \left(\frac{c^2}{a^4b}\right)^{1/2}=\frac c{a^2\sqrt{b}}$ Does that make sense?
Yes that makes sense, but according to my math book the answer is $\displaystyle \frac{c\sqrt{b}}{a^2 b}$ .
Last edited by Coach; Sep 4th 2007 at 09:37 AM.
Originally Posted by Coach Yes that makes sense, but according to my math book the answer is $\displaystyle \frac{c\sqrt{b}}{a^2 b}$ . What's the matter? Multiply numerator and denominator by $\displaystyle \sqrt b$ to my answer and you'll get the desired.
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