Could someone please help me with this?

((a^4)b)/(c^2)^^-1/2

Thank you!

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- Sep 4th 2007, 08:22 AMCoachProblems with indices
Could someone please help me with this?

((a^4)b)/(c^2)^^-1/2

Thank you! - Sep 4th 2007, 08:26 AMKrizalid
Not much you can do from there...

$\displaystyle \left(\frac{a^4b}{c^2}\right)^{-1/2}$

Is this thing you wanna reduce? - Sep 4th 2007, 08:54 AMCoach
Yes, I am sorry I do not know how to use tags.

I tried to take away the fractions by multiplying by a^2 and c, but I couldn't

get the right answer. - Sep 4th 2007, 08:58 AMKrizalid
See the LaTeX Tutorial

Now, we have that $\displaystyle \left(\frac{c^2}{a^4b}\right)^{1/2}=\frac c{a^2\sqrt{b}}$

Does that make sense? - Sep 4th 2007, 09:16 AMCoach
Yes that makes sense, but according to my math book the answer is $\displaystyle \frac{c\sqrt{b}}{a^2 b}$ .

- Sep 4th 2007, 10:12 AMKrizalid