help im stuck is this possible to factorise? 3(x^2-10x+16) = (x+10)(x-8) ???
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This is obviously not correct as there was a factor of 3 that disappeared. I think you'll find that the two numbers that multiply to give 16 and add to give -10 are -8 and -2.
Originally Posted by dragon555 help im stuck is this possible to factorise? 3(x^2-10x+16) = (x+10)(x-8) ??? Since 10(-8)= -80 is NOT 3(16)= 48, no those are obviously not the same. You could do it this way: which is a "sum and difference of squares"- it is equal to .
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