help im stuck
is this possible to factorise?
3(x^2-10x+16)
= (x+10)(x-8) ???
Since 10(-8)= -80 is NOT 3(16)= 48, no those are obviously not the same.
You could do it this way: $\displaystyle x^2- 10x+ 16= x^2- 10x+ 25- 9= (x- 5)^2- 9$ which is a "sum and difference of squares"- it is equal to $\displaystyle ((x-5)+3)((x-5)-3)= (x-2)(x-8)$.
$\displaystyle 3(x^2- 10x+ 16)= 3(x- 2)(x- 8)$