How do I find the vertex?
I set y to zero then I get -3? I think.
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Can you find the vertex of ?
Your function is stretched and shifted version of . Identify the transformation and you will see where the new vertex is.
No, you do NOT set y equal to 0. That would give the y-intercept which, in general, has nothing to with the vertex.
Since a square is never 0, , is never less than -3. It is -3 when the square is 0- that is, when y+ 1= 0.
it helps to write out the standard form formula. then you can see what its telling you. vertex=(h,k)
you also know your values are inverted.
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