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Math Help - algebra - radicals and rational exponent problem

  1. #1
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    algebra - radicals and rational exponent problem

    \left( \frac{a^{-3/m} \cdot b^{6/n}}{a^{-6/m} \cdot b^{9/n}}\right)^{-1/3}

    thats the orginal problem, heres my work

    \left( \frac{a^{6/m} \cdot b^{6/n}}{a^{3/m} \cdot b^{9/n}}\right)^{-1/3}


    \left( {a^{3/m} \cdot b^{-3/n}}\right)^{-1/3}


    ok iam having extreme difficulty w/ latex past this point so ill write out what i did from this step, so i flipped them again w/ the positive b^3/n on top and a^3/m on bottom, then applied the positive 1/3 to each and my wrong answer is b^n over a^m

    the answer from a algebra problem solver i have is 1/a^1/m b^5/n

    i have no idea where i went wrong, sorry i couldnt finish up in latex
    Last edited by mathmathmathmathmathmathm; July 16th 2011 at 09:05 AM.
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  2. #2
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    Re: algebra - radicals and rational exponent problem

    .....................
    Last edited by mathmathmathmathmathmathm; July 16th 2011 at 09:06 AM.
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  3. #3
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    Re: algebra - radicals and rational exponent problem

    Quote Originally Posted by mathmathmathmathmathmathm View Post
    a^(6/m) * b^(9/n)^(-1/3)[/tex]

     \frac{a^(-3/m) * b^(6/n)}{a^(6/m) * b^(9/n)^(-1/3}
    If there is more that one character in an exponent you must use {}.
    [tex]\left( \frac{a^{-3/m} \cdot b^{6/n}}{a^{6/m} \cdot b^{9/n}}\right)^{-1/3} [/tex]
    \left( \frac{a^{-3/m} \cdot b^{6/n}}{a^{6/m} \cdot b^{9/n}}\right)^{-1/3}
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