This is a complex quadratic, so you can proceed by completing the square,Originally Posted byphgao

or using the quadratic formula to find its roots and then the

factorisation is:

.

So lets simplify the equation a bit:

The only problem will be finding the square root of the discriminant.

In this case the discriminant is:

We need the square root of this. We proceed by converting the discriminant

to polar form, then finding the square root by square-rooting the modulus and

halving the argument. Or as MathWorld would put it:

,

Which should allow you to complete the factorisation.

RonL