This isn't urgent, but I'd like explanations + working out so I can understand the question. THanks!

Factorise:

2z^2 + 2(z-2)z +3/2 - 6i

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- February 9th 2006, 08:27 PMphgaoFactorisation
This isn't urgent, but I'd like explanations + working out so I can understand the question. THanks!

Factorise:

2z^2 + 2(z-2)z +3/2 - 6i - February 10th 2006, 12:01 AMCaptainBlackQuote:

Originally Posted by**phgao**

or using the quadratic formula to find its roots and then the

factorisation is:

.

So lets simplify the equation a bit:

The only problem will be finding the square root of the discriminant.

In this case the discriminant is:

We need the square root of this. We proceed by converting the discriminant

to polar form, then finding the square root by square-rooting the modulus and

halving the argument. Or as MathWorld would put it:

,

Which should allow you to complete the factorisation.

RonL