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Math Help - Help with simplifying square roots

  1. #1
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    Help with simplifying square roots

    Well, my teacher explained to use how to simplify squares roots but i forgot how to do it, and now i have to finsh the homework. Can any1 explain to me how to do this? Here are some problems i have to do.
    square root of 12, -square root-200, and 5 square root 50 - 3 square root 2 +4 square root 8
    the - are negatives.
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  2. #2
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    \sqrt{12}=\sqrt{2^2\times3}

    Can you take it from there?
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  3. #3
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    she taught us how to Break it down to like 12 to square root 2 x square root 6
    then square root 2 x square root 2 x square root 2. But i forgot how to finish it.
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  4. #4
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by Krizalid View Post
    \sqrt{12}=\sqrt{2^2\times3}

    Can you take it from there?
    Quote Originally Posted by d4rkh4z3 View Post
    she taught us how to Break it down to like 12 to square root 2 x square root 6
    then square root 2 x square root 2 x square root 2. But i forgot how to finish it.
    Do you mean \sqrt{12} = \sqrt{2} \sqrt{2} \sqrt{3}? How bizarre!

    Well, note that you have two factors of \sqrt{2}, so \sqrt{2}\sqrt{2} = 2 and we have:
    \sqrt{12} = \sqrt{2} \sqrt{2} \sqrt{3} = 2\sqrt{3}.

    I find it easier (and faster) using Krizalid's method:
    \sqrt{12} = \sqrt{2^2 \cdot 3} = \sqrt{2^2} \sqrt{3} = 2 \sqrt{3}
    where I have included some steps that many would skip after some amount of experience.

    -Dan
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