Thread: Parallel and perpendicular lines?

Write an equation of the line through the point that is parallel to the given line and perpendicular.


Point (7/8,3/4) line 5x+3y=0

which I turned into y=-5/3x

Then I plug into

(y-3/4)= -5/3(x-7/8) This is for parallel

3(3/4)=-5(x-7/8) Did I set this up correct


My second question is

(2,5) x=4 how would I set it up if the slope is undefined?

Originally Posted by homeylova223

Write an equation of the line through the point that is parallel to the given line and perpendicular.
(2,5) x=4

Given the line and point
one answer is and the other is .
Which is which?

Hmm I guess x=2 would be the parallel and y=5 perpendicular

Originally Posted by homeylova223

Hmm I guess x=2 would be the parallel and y=5 perpendicular

Correct.

Would this be parallel for my first question

3(y-3/4)=-5(x-7/8)

3y-2.25=-5x+4.375
3y=-5x+6.625

y=-5/3x+6.625/3 ?

Originally Posted by homeylova223

Write an equation of the line through the point that is parallel to the given line and perpendicular.


Point (7/8,3/4) line 5x+3y=0

which I turned into y=-5/3x

Then I plug into

(y-3/4)= -5/3(x-7/8) This is for parallel

3(3/4)=-5(x-7/8) Did I set this up correct

[snip]

Yes.