Write an equation of the line through the point that is parallel to the given line and perpendicular.
Point (7/8,3/4) line 5x+3y=0
which I turned into y=-5/3x
Then I plug into
(y-3/4)= -5/3(x-7/8) This is for parallel
3(3/4)=-5(x-7/8) Did I set this up correct
My second question is
(2,5) x=4 how would I set it up if the slope is undefined?