Write an equation of the line through the point that is parallel to the given line and perpendicular.

Point (7/8,3/4) line 5x+3y=0

which I turned into y=-5/3x

Then I plug into

(y-3/4)= -5/3(x-7/8) This is for parallel

3(3/4)=-5(x-7/8) Did I set this up correct

My second question is

(2,5) x=4 how would I set it up if the slope is undefined?