Parallel and perpendicular lines?

Write an equation of the line through the point that is parallel to the given line and perpendicular.

Point (7/8,3/4) line 5x+3y=0

which I turned into y=-5/3x

Then I plug into

(y-3/4)= -5/3(x-7/8) This is for parallel

3(3/4)=-5(x-7/8) Did I set this up correct

My second question is

(2,5) x=4 how would I set it up if the slope is undefined?(Headbang)

Re: Parallel and perpendicular lines?

Quote:

Originally Posted by

**homeylova223** Write an equation of the line through the point that is parallel to the given line and perpendicular.

(2,5) x=4

Given the line $\displaystyle x=4$ and point $\displaystyle (2,5)$

one answer is $\displaystyle y=5$ and the other is $\displaystyle x=2$.

Which is which?

Re: Parallel and perpendicular lines?

Hmm I guess x=2 would be the parallel and y=5 perpendicular

Re: Parallel and perpendicular lines?

Quote:

Originally Posted by

**homeylova223** Hmm I guess x=2 would be the parallel and y=5 perpendicular

Correct.

Re: Parallel and perpendicular lines?

Would this be parallel for my first question

3(y-3/4)=-5(x-7/8)

3y-2.25=-5x+4.375

3y=-5x+6.625

y=-5/3x+6.625/3 ?

Re: Parallel and perpendicular lines?

Quote:

Originally Posted by

**homeylova223** Write an equation of the line through the point that is parallel to the given line and perpendicular.

Point (7/8,3/4) line 5x+3y=0

which I turned into y=-5/3x

Then I plug into

(y-3/4)= -5/3(x-7/8) This is for parallel

3(3/4)=-5(x-7/8) Did I set this up correct

[snip]

Yes.