Since 1/2 is a root then you know that where A and B are constants.
Comparing coefficients
To find the value of B you can compare the coefficients of x. Once you have B it should be easy to find k
Can anybody help... how is it possible to find the root of 16x^2-24x+k = 0 ? when one root is 1/2 and find k?
it is possible to find the value of k if the sum and product of the roots are equal?
if im going to solve i understand that in the k is the c part of quadratic equation.
so,
k = c/a = k/16 then in this part i am stuck.
it made me solve for hours but still can't get the answer correctly.
thank you so much and more power.
-B = k
and that is -24 = k is this correct sir? or should i have to make it -24 = r1 + r2; - 24 = 1/2 + r2 then -24 -1/2 = r2, then r2 = -24 1/2 which the other root now. Oh my gosh please hope this is right.