# Math Help - kindly explain the step

1. ## kindly explain the step

how he is using the d
plz do in simple steps
file attached

2. ## Re: kindly explain the step

If you write:
$\sqrt{(h_t+h_r)^2+d^2}$ as $\sqrt{d^2\cdot\left(\frac{(h_t+h_r)^2}{d^2}+1 \right)}= ...$
Can you complete? ...
For the other term it's similar.

3. ## Re: kindly explain the step

First take the d^2 as a common factor for both terms and then work from there..
i.e (ht + hr)^2 +d^2 = d^2 [(ht+hr)^2 / d^2 + 1]

4. ## Re: kindly explain the step

other term is delta

5. ## Re: kindly explain the step

Originally Posted by Goku
First take the d^2 as a common factor for both terms and then work from there..
i.e (ht + hr)^2 +d^2 = d^2 [(ht+hr)^2 / d^2 + 1]
yes i am also dowing like this but why he has written simple d as a common factor
it should be d^2 as u wrote

6. ## Re: kindly explain the step

Because you have to take the square root.

7. ## Re: kindly explain the step

take the square root of d^2 [(ht+hr)^2 / d^2 + 1], this whole term is underneath a square root...
(d^2 [(ht+hr)^2 / d^2 + 1])^1/2 = d [(ht+hr)^2 / d^2 + 1]^1/2

8. ## Re: kindly explain the step

no it is not working
can u show me these simple steps
thanks a lot

9. ## Re: kindly explain the step

Originally Posted by Goku
take the square root of d^2 [(ht+hr)^2 / d^2 + 1], this whole term is underneath a square root...
(d^2 [(ht+hr)^2 / d^2 + 1])^1/2 = d [(ht+hr)^2 / d^2 + 1]^1/2
Thanks a lot Goku
it is solved now

10. ## Re: kindly explain the step

x = d^2

y = (ht+hr)^2 / d^2 + 1