# kindly explain the step

• Jul 9th 2011, 12:35 AM
moonnightingale
kindly explain the step
how he is using the d
plz do in simple steps
file attached
• Jul 9th 2011, 12:42 AM
Siron
Re: kindly explain the step
If you write:
$\displaystyle \sqrt{(h_t+h_r)^2+d^2}$ as $\displaystyle \sqrt{d^2\cdot\left(\frac{(h_t+h_r)^2}{d^2}+1 \right)}= ...$
Can you complete? ...
For the other term it's similar.
• Jul 9th 2011, 12:44 AM
Goku
Re: kindly explain the step
First take the d^2 as a common factor for both terms and then work from there..
i.e (ht + hr)^2 +d^2 = d^2 [(ht+hr)^2 / d^2 + 1]
• Jul 9th 2011, 12:45 AM
moonnightingale
Re: kindly explain the step
other term is delta
• Jul 9th 2011, 12:48 AM
moonnightingale
Re: kindly explain the step
Quote:

Originally Posted by Goku
First take the d^2 as a common factor for both terms and then work from there..
i.e (ht + hr)^2 +d^2 = d^2 [(ht+hr)^2 / d^2 + 1]

yes i am also dowing like this but why he has written simple d as a common factor
it should be d^2 as u wrote
• Jul 9th 2011, 12:51 AM
Siron
Re: kindly explain the step
Because you have to take the square root.
• Jul 9th 2011, 12:51 AM
Goku
Re: kindly explain the step
take the square root of d^2 [(ht+hr)^2 / d^2 + 1], this whole term is underneath a square root...
(d^2 [(ht+hr)^2 / d^2 + 1])^1/2 = d [(ht+hr)^2 / d^2 + 1]^1/2
• Jul 9th 2011, 12:53 AM
moonnightingale
Re: kindly explain the step
no it is not working
can u show me these simple steps
thanks a lot
• Jul 9th 2011, 12:54 AM
moonnightingale
Re: kindly explain the step
Quote:

Originally Posted by Goku
take the square root of d^2 [(ht+hr)^2 / d^2 + 1], this whole term is underneath a square root...
(d^2 [(ht+hr)^2 / d^2 + 1])^1/2 = d [(ht+hr)^2 / d^2 + 1]^1/2

Thanks a lot Goku
it is solved now
• Jul 9th 2011, 12:55 AM
Goku
Re: kindly explain the step