hi,
i need to know how to write the gradient of the line perpendicular to Y=3x+1.
i don't really know how to do this and some help would be great!!!
thanks!
p.s. sorry if topic is in wrong place, wasn't sure where to post.
Okay. Can we go through this one step at a time?
1. Is the gradient 1/3?
2. If so is the gradient of the line perpendicular to Y=3x+1 =-3/1?
3. Again, if so would the final answer be Y=-3/1x+1?
If this is not correct can you point out which step of what i have said is wrong please.
You have the equation of the (given) line:
y=3x+1
And now you've found the gradient of a line perpendicular to y as you know.
In y the 1 is the point at which the line y crosses the y-axis, this hasn't to be the same for the line perpendicular to y, you've a lot of options. You only have the choose one.
(You only have one option when they ask to give the equation of the line perpendicular to y and going through a given point)
So maybe it's a little bit confusing but draw y=3x+1, now draw a line perpendicular to y and look where that line crosses the y-axis so you can create the equation of the line perpendicular to y.
Is that clear or? ...