Thread: Two word problems.

First:

A company purchases a billboard on the side of the highway for $10,000. For each person that calls the number on the billboard and fills out an application, the company receives $100. 15% of people who call the number actually fill out an application. What is the minimum number of calls that need to be made so that the company can make a profit off the billboard?

Second:

A company sends out an email to 1,000,000 people to register for an event. The email has a 8% open rate, 5% click-through rate, 200 registrations at $10/registration. What is the cost per click?

I had a hard time with these two at a recent interview.

Thanks in advance.

For the first one,

Let x be the amount of people filling out an application

Let y be the total amount of people calling

Solve the system:

100x = 10000

0.15y = x

What do you get?

x = 100
y = 667 people

Correct?

I'm pretty sure.

But why don't you check it yourself?

I.e. is 100 equal to 15% of 667?

Hello, llckll!

A company purchases a billboard on the side of the highway for $10,000.
For each person that calls the number on the billboard and fills out an application,
the company receives $100.
15% of people who call the number actually fill out an application.

What is the minimum number of calls that need to be made
so that the company can make a profit off the billboard?

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WHY are about 99% of problems called "word problems"?!

Do you have a confidence interval for that proportion Wilmer?

Originally Posted by pickslides

Do you have a confidence interval for that proportion Wilmer?

That sounds like a "word problem"!