# Math Help - Getting the standard form of ellipse.

1. ## Getting the standard form of ellipse.

Hey guys,
How do I convert this equation:

$4x^2 -4x +8y^2 +48y = -57$
into the standard form of an ellipse's formula.

I know that the right hand side has to be 1 but O don't know what to do with the first degree x and y terms.

2. ## Re: Circle formula

Originally Posted by elieh
$4x^2 -4x +8y^2 +48y = -57$
into the standard form of an ellipse's formula.
I'll get you started.
$4x^2 -4x +8y^2 +48y=4(x-0.5)^2+8(y+3)^2-1-72$.

You should expand that to check my work.

3. ## Re: Circle formula

Got it!

$\frac{(x-0.5)^2}{4} + \frac{(y+3)^2}{2} =1$

4. ## Re: Circle formula

In other words, complete the square.

5. ## Re: Circle formula

You'll find that whenever you want a circle or ellipse, completing the square is required.