solving this algebraically , If t ties cost d dollars, how many dollars would t+1 ties cost ?? note:show your answer...
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Originally Posted by omar1 solving this algebraically , If t ties cost d dollars, how many dollars would t+1 ties cost ?? note:show your answer... one tie would cost d/t dollars ... so, how much would t+1 ties cost?
okay.... this is how I would do it: one tie = d/t so t+1 must be (d+t)/t got it? you add one to each side . hope it helps.
Originally Posted by IBstudent okay.... this is how I would do it: one tie = d/t so t+1 must be (d+t)/t got it? you add one to each side . hope it helps. and that would be incorrect
:O but look: t= d/t t+1 = d/t +1 t+1 = (d+t)/t where is the wrong bit? Edit: even substituding works: say 50 ties each costing 5 dollars 10 = 50/5 10+1= (50+5)/5 11=55/5 11=11 Thanks
ties cost dollars 1 tie costs dollars adding the cost for t ties and 1 tie ... which does not equal note ... ... which is the cost of one tie times (t+1) ties
Originally Posted by IBstudent :O but look: t= d/t Well, your very first equation is wrong! t+1 = d/t +1 t+1 = (d+t)/t where is the wrong bit? Edit: even substituding works: say 50 ties each costing 5 dollars 10 = 50/5 10+1= (50+5)/5 11=55/5 11=11 Thanks
Originally Posted by HallsofIvy Well, your very first equation is wrong! Ouch! Thank you for pointing that out though...
Originally Posted by skeeter ties cost dollars 1 tie costs dollars adding the cost for t ties and 1 tie ... which does not equal note ... ... which is the cost of one tie times (t+1) ties 5/5 exact answer....
Last edited by mr fantastic; June 25th 2011 at 03:20 PM. Reason: Deleted excess smilies.
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