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Math Help - If t ties cost d dollars...

  1. #1
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    If t ties cost d dollars...

    solving this algebraically , If t ties cost d dollars, how many dollars would t+1 ties cost ??

    note:show your answer...
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  2. #2
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    re: If t ties cost d dollars...

    Quote Originally Posted by omar1 View Post
    solving this algebraically , If t ties cost d dollars, how many dollars would t+1 ties cost ??

    note:show your answer...
    one tie would cost d/t dollars ... so, how much would t+1 ties cost?
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  3. #3
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    Re: If t ties cost d dollars...

    okay....
    this is how I would do it:
    one tie = d/t
    so t+1 must be (d+t)/t
    got it? you add one to each side .

    hope it helps.
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  4. #4
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    Re: If t ties cost d dollars...

    Quote Originally Posted by IBstudent View Post
    okay....
    this is how I would do it:
    one tie = d/t
    so t+1 must be (d+t)/t
    got it? you add one to each side .

    hope it helps.
    and that would be incorrect
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  5. #5
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    Re: If t ties cost d dollars...

    :O
    but look:
    t= d/t
    t+1 = d/t +1
    t+1 = (d+t)/t
    where is the wrong bit?

    Edit: even substituding works:
    say 50 ties each costing 5 dollars
    10 = 50/5
    10+1= (50+5)/5
    11=55/5
    11=11

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  6. #6
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    Re: If t ties cost d dollars...

    t ties cost d dollars

    1 tie costs \frac{d}{t} dollars

    adding the cost for t ties and 1 tie ...

    d + \frac{d}{t} which does not equal \frac{d+t}{t}

    note ...

    d + \frac{d}{t} = \frac{dt}{t} + \frac{d}{t} = \frac{dt+d}{t} = \frac{d(t+1)}{t} = \frac{d}{t}(t+1)

    ... which is the cost of one tie times (t+1) ties
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  7. #7
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    Re: If t ties cost d dollars...

    Quote Originally Posted by IBstudent View Post
    :O
    but look:
    t= d/t
    Well, your very first equation is wrong!

    t+1 = d/t +1
    t+1 = (d+t)/t
    where is the wrong bit?

    Edit: even substituding works:
    say 50 ties each costing 5 dollars
    10 = 50/5
    10+1= (50+5)/5
    11=55/5
    11=11

    Thanks
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  8. #8
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    Re: If t ties cost d dollars...

    Quote Originally Posted by HallsofIvy View Post
    Well, your very first equation is wrong!
    Ouch!
    Thank you for pointing that out though...
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  9. #9
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    Re: If t ties cost d dollars...

    Quote Originally Posted by skeeter View Post
    t ties cost d dollars

    1 tie costs \frac{d}{t} dollars

    adding the cost for t ties and 1 tie ...

    d + \frac{d}{t} which does not equal \frac{d+t}{t}

    note ...

    d + \frac{d}{t} = \frac{dt}{t} + \frac{d}{t} = \frac{dt+d}{t} = \frac{d(t+1)}{t} = \frac{d}{t}(t+1)

    ... which is the cost of one tie times (t+1) ties



    5/5 exact answer....
    Last edited by mr fantastic; June 25th 2011 at 02:20 PM. Reason: Deleted excess smilies.
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