
Transposing question
(New here, hope I'm posting in the right forum...)
Hello! I am working on a set of 30 problems to do with transposing equations. I have been doing well up until now, but I have hit this at question 28:
y = (a + x) / (5  bx) rearranged for x
I know that the answer should be:
x = (5y  a) / (1 + by)
My working so far is:
y(5  bx) = a + x
5y  ybx = a + x
...and now I get stuck. I can't seem to isolate x. I see that both the question and answer are equal but I don't see how they got there (also confused where the constant "1" came from). Any help with this would be greatly appreciated!

Re: Transposing question
Looks good so far
$\displaystyle 5y  ybx = a + x$
Now put the x's on the same side.
$\displaystyle 5y a= x+ybx$
Factor out x.
$\displaystyle 5y a= x(1+yb)$
Finish him off.

Re: Transposing question
Ah thank you very much. My knowledge of factoring was lacking and I didn't see I could do it there. Sorted!