I am so lost.. Can somebody help me how to solve this:
Determine X when:
2X^4,6 = 512x^0,6
Correct. Now what do you suppose you could do next? You have x raised to a power on both sides of the equation. You'd like to isolate x on one side of the equation. Is there an operation you could do to both sides of the equation that will move you in that direction?
[EDIT]: You should only have divided the coefficients by two, not the exponents.
Wow, thanks a lot! When it is displayed like that, it seems very simple! I get it now. Thanks again.
But another question, I have to determine the regulation of the Power Equation, when the following two points, is on the power equations graph:
(2,4) and (4,32)
How in earth is that done? Or how do I just get started with it?
Thanks a lot in advance, what a great forum!
A "power equation" is of the form $\displaystyle y= Ax^k$. If y= 4 when x= 2, then $\displaystyle 4= A(2^k)$. If y= 32 when x= 4, $\displaystyle 32= A(4^k)$.
Solve those two equations for A and k. (Trying eliminating A first by dividing one equation by the other.)
Right. What Prove It should have said was
$\displaystyle x^{4.6}= 256x^{0.6}$
If x is not 0
then $\displaystyle \frac{x^{4.6}}{x^{0.6}}= x^4= 256$
$\displaystyle x= \pm 4$
so the three real roots are 0, 4 and -4.
We could also note that $\displaystyle x^2= \pm 16$ so taking the negative root, $\displaystyle x^2= -16$ gives the two imaginary roots $\displaystyle x= \pm 4i$.