How in the world would I do a problem like this?! it's: 18 _______ (9^(3/2) In case you're not sure if you read that right or not, it would be read: 18 over 9 to the 3/2 power.
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Originally Posted by deathtolife04 How in the world would I do a problem like this?! it's: 18 _______ (9^(3/2) In case you're not sure if you read that right or not, it would be read: 18 over 9 to the 3/2 power. what are you required to do? simplify? if so, change 18 to 2*9, pull the 2 out in front, and then see if you can take it from there
Originally Posted by Jhevon what are you required to do? simplify? if so, change 18 to 2*9, pull the 2 out in front, and then see if you can take it from there oooh ok so wouldn't it just be 2/3? that was easier than it looked!
Originally Posted by deathtolife04 oooh ok so wouldn't it just be 2/3? that was easier than it looked! yes it was, good job!
Originally Posted by deathtolife04 How in the world would I do a problem like this?! it's: 18 _______ (9^(3/2) In case you're not sure if you read that right or not, it would be read: 18 over 9 to the 3/2 power. $\displaystyle \frac{18}{9^{3/2}}$ Or you could simply note that: $\displaystyle 9^{3/2} = \left ( 9^{1/2} \right ) ^3 = 3^3 = 27$ So $\displaystyle \frac{18}{9^{3/2}} = \frac{18}{27} = \frac{2}{3}$ -Dan
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