Second Opinion On Hw Answer

**sasha9193** · August 31st 2007, 01:45 PM

X/5X-6 - 3X/2X-5 =

<br><br>INTO ONE SIMPLE FRACTION FORM

USING MY TECHNIQUE I GOT AN ANSWER, PLZ SOME OTHER PPL SUBMIT THE ANSWER THEY GET CUS IT IS VERY IMPORTANT AND WANT TO MAKE SURE I HAVNT MADE ANY SILLY MISTAKES<br>

**red_dog** · August 31st 2007, 01:49 PM

Write your answer first, to see if it's correct.

**sasha9193** · August 31st 2007, 01:52 PM

I GOT 2Xsquared-2X/15Xsquared-37X+30

**sasha9193** · August 31st 2007, 01:58 PM

Red dog u do it, wot u get? i wouldnt be so needy but its like really important i get this right

**red_dog** · August 31st 2007, 02:02 PM

$\displaystyle\frac{x}{5x-6}-\frac{3x}{2x-5}=\frac{x(2x-5)-3x(5x-6)}{(5x-6)(2x-5)}=$
$\displaystyle =\frac{-13x^2+13x}{10x^2-37x+30}$

**Soroban** · August 31st 2007, 02:15 PM

Hello, Sasha!

Don't know what "your technique" is . . . but it's wrong.

$\frac{x}{5x-6} - \frac{3x}{2x-5}$

We need a lowest common denominator
. . so we "convert" the fractions to the LCD.

$\frac{x}{5x-6}\cdot{\color{blue}\frac{2x-5}{2x-5}} - \frac{3x}{2x-5}\cdot{\color{blue}\frac{5x-6}{5x-6}} \;\;= \; \;\frac{x(2x-5) - 3x(5x-6)}{(5x-6)(2x-5)}$

. . $= \;\frac{2x^2 - 5x - 15x^2 + 18x}{(5x-6)(2x-5)} \;=\;\frac{-13x^2 + 13x}{(5x-6)(2x-5)} \;\;= \;\;\boxed{\frac{-13x(x-1)}{(5x-6)(2x-5)}}$

Thread: Second Opinion On Hw Answer

LinkBack

Thread Tools

Display

Second Opinion On Hw Answer

Similar Math Help Forum Discussions

[SOLVED] what is your opinion in that problem

I could use a second opinion on the completeness of my solution...

Opinion on proof!

Other opinion needed

my opinion about HP's

Search Tags