Out of 42 kids in a class twice as many failed Ela as math,4 failed both. If 7 failed neither, find how many failed each subject.
Please show your work thanks
This is your problem- show some of your work! I recommend a "Venn diagram" that consists of two overlapping circles, one representing the students who passed math, one representing the students who passed Ela (?) If "7 failed neither" there are 7 students in the overlap.
Then you need to say exactly what you tried to do and where you get stuck.
Here is the equation you need to solve:
x + 4 + [2(x+4) - 4] + 7 = 42.
Yes, the equation is useless without a Venn diagram to justify it - your job is to draw the Venn diagram (as suggested - quite helpfully I might add - in post #2) and justify the above equation. However, I'd suggest using circles that represent students who failed (which is what I did).
Out of 42 kids in a class twice as many failed Ela as math,4 failed both. If 7 failed neither,
find how many failed each subject.
I made a venn diagram the middle part of the venn diagram would be 7 and the math part would be 13 and the ela part would be 26. How do i check this?
The middle part of mine is 4 (see my earlier post for why, and where 4 appears in my equation). Yes, a total of 13 students FAILED maths, and a total of 26 students FAILED Ela. Obviously a good way of checking these answers would be to see if they are consistent with the information given in the question.
As you say, 13 failed math and 26 failed Ela (What is "Ela"? Must be a tough subject!) that would be a total of 13+ 26= 39 except that, since four students failed both that counts those four twice- actually 39- 4= 35 students failed one or the other or both. Since 7 students did not fail either, there are 35+ 7= 42 students total which is what we are told.