# Thread: Rectangle expressions, formula and graphing

1. ## Rectangle expressions, formula and graphing

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I think the wording of the question throws me, I wondering if someone can have a look at what I have come up with and tell me if I am on the right track.

For (a) all I can think of is X < L

For (b) I get

A = X * (100 - X) / 2

Graphing this I get a parabola which I would expect.

For (d) even without looking at the graph I know the width can't exceed the length

so I assume x = 49.9 at its largest area as when x is 50 the length is then 50 and its

a square.

Knowing that then the dimensions for the largest possible area would be 49.9 X 50.1

I apologize if all that is astronomically incorrect but any input would be greatly appreciated.

2. I'll get you started.

If you ignore the context of this question, we have a 3 sided rectangle. 2 of the sides are x metres and you have 100 metres of wire netting. Wouldn't the other length be $\displaystyle 100-2x$ ?

3. Thanks for your reply so as the question states that one side is a pre existing wall, I

understand what you said but the problem I have is the equation does not say

whether it is the wall opposite X that is existing or the one opposite the length.

What I got for the area I assume would depend on which one it is ie:

If it where opposite x I get = A = X * (100 - X) / 2

If it was one of the lengths = A = X * (100 - 2X)