I'll get you started.
If you ignore the context of this question, we have a 3 sided rectangle. 2 of the sides are x metres and you have 100 metres of wire netting. Wouldn't the other length be ?
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I think the wording of the question throws me, I wondering if someone can have a look at what I have come up with and tell me if I am on the right track.
For (a) all I can think of is X < L
For (b) I get
A = X * (100 - X) / 2
Graphing this I get a parabola which I would expect.
For (d) even without looking at the graph I know the width can't exceed the length
so I assume x = 49.9 at its largest area as when x is 50 the length is then 50 and its
a square.
Knowing that then the dimensions for the largest possible area would be 49.9 X 50.1
I apologize if all that is astronomically incorrect but any input would be greatly appreciated.
Thanks for your reply so as the question states that one side is a pre existing wall, I
understand what you said but the problem I have is the equation does not say
whether it is the wall opposite X that is existing or the one opposite the length.
What I got for the area I assume would depend on which one it is ie:
If it where opposite x I get = A = X * (100 - X) / 2
If it was one of the lengths = A = X * (100 - 2X)