I just want to understand how you get the three when you have to cube three binomials together.
my tutor gave me this formula to follow when i come across anything I have to cube. However I'm not sure how she got the 3 there.
I just want to understand how you get the three when you have to cube three binomials together.
my tutor gave me this formula to follow when i come across anything I have to cube. However I'm not sure how she got the 3 there.
His point is that there are terms (a)(a)(b), (a)(b)(a), and (b)(a)(a) that come up. Since there are three of them, you get a 3 in front of the .
However let's look at this differently. , right? Then you expand and simplify to get . The 2 in front of the ab appears because we have a term ab and ba.
Similarly:
Expand this and simplify. Here you will find, for instance, that you have a and a which gives you .
-Dan
The order doesn't matter in multiplication - 5*3 is the same as 3*5. This extends to letters too so and since you have three lots in your expansion it gives
If "proving" it isn't all that important look up Pascal's triangle - that gives you the coefficients necessary. Or, better yet, the binomial theorem