# How do I factor this since it has no common GCF?

• Aug 29th 2007, 08:51 PM
deathtolife04
How do I factor this since it has no common GCF?
I'm not really sure what to do in this situation?

\$\displaystyle 6p^2+p-12\$
?
• Aug 29th 2007, 08:53 PM
Jhevon
Quote:

Originally Posted by deathtolife04
I'm not really sure what to do in this situation?

\$\displaystyle 6p^2+p-12\$
?

foil

play around with the factors of 6p^2, your possibilities are:

(6p + ?)(p + ?)

or

(2p + ?)(3p + ?)

so now, find the ?'s using the suitable set of brackets
• Aug 29th 2007, 09:03 PM
deathtolife04
Quote:

Originally Posted by Jhevon
foil

play around with the factors of 6p^2, your possibilities are:

(6p + ?)(p + ?)

or

(2p + ?)(3p + ?)

so now, find the ?'s using the suitable set of brackets

so, it would be: (2p+3)(3p-4), right? :rolleyes:
• Aug 29th 2007, 09:12 PM
Jhevon
Quote:

Originally Posted by deathtolife04
so, it would be: (2p+3)(3p-4), right? :rolleyes:

correct! :)

(you know, you can expand the brackets to see if you get back the original expression, as a check)