1. ## solve by elimination

I need help please solving the following with the elimination method:
3r-2s=17 and 2r+3s=33 Thanks for any help!

2. Originally Posted by jay1
I need help please solving the following with the elimination method:
3r-2s=17 and 2r+3s=33 Thanks for any help!
I would recommend eliminating the variable 's' because one of the 's' variables in the system is negative. So now, what is the least common multiple of 2 and 3? Keeping that in mind, multiply each equation by the "missing factor" in the least common multiple. Next, add the two equations together; if you did everything correctly, the 's' variable should drop out and you'll be left with something of the form $ar=b$ which is relatively simple to solve. Lastly, now that you know 'r', you can plug it into either equation to find 's'.

I hope you can make sense of this. Please post back if you have further difficulties.

3. HINT:
a + b = 20
a - b = 12
========
2a = 32