I was supposed to factor , and following the steps I ended up with I don't think that's factored COMPLETELY though?
Then I was supposed to factor , and I got . I don't think that's factored completely either?! Were there different steps I was supposed to follow or something?
your input would be greatly appreciated!
thanks!
I don't think I'm familiar with a formula for factoring expressions like the first one.
Yes, I've heard of foiling. I think it may be starting to come back to me, how to turn them into 'foil' problems. Is that the thing where I would need to find two numbers whose product is 48, and the sum would have to be -32? And then you somehow turn that into a 'foil' problem? I can't remember exactly...
here's the formula. try it and tell me what you get.
Yes, I've heard of foiling. I think it may be starting to come back to me, how to turn them into 'foil' problems. Is that the thing where I would need to find two numbers whose product is 48, and the sum would have to be -32? And then you somehow turn that into a 'foil' problem? I can't remember exactly...[/quote]you already made it simpler didn't you? by factoring out the 4? don't worry about 48 and 32, now all you have to worry about is 8 and 12. (By the way, if you are factoring the original expression, it would be even harder, since the coeffcient of is not 1. with experience you should be able to foil it, but beginners have this whole process they have to go through to factor by groups and stuff.
anyway, you were right so far, now you just have to put it together. let's say the two numbers you found were and (and they can be positive or negative), then the answer would be in the form:
contracting the original expression into that form is called "foiling." try it
This is my 31th post!!!!
ok, yeah, that sounds better
so for the second one I figured out that -6 and -2 have a product of 12 and a sum of -8
so, how would i write my final answer? i think if i just write it 4(n-6)(n-2) that would be wrong? cuz then it would look like you just had to distribute the 4 to the n-6?????
write (2n - 12)(2n - 4)
i split the 4 into 2 times 2, distributed one 2 in the first set of brackets and the other in the second. it is what you would get if you foiled directly
on second thought, i think it may be better if you keep the constants out in front, it looks messier, but it is factored "completely" when in that form