y=x^3 and Z=loge(x+1). Hence, using addition of ordinates, sketch the grph of w=z-y. use domain of (-1,-2].
please i need help with this what would be the new set of points. i dont get it
y=x^3 and Z=loge(x+1). Hence, using addition of ordinates, sketch the grph of w=z-y. use domain of (-1,-2].
please i need help with this what would be the new set of points. i dont get it
You probably mean the segment (-1,2]. (Why do we have to guess?)
Draw both graphs. Note approximately their intersection points. The difference will be zero in these points. Determine where the difference w is positive and negative. Calculate the value (approximately) of w for x = 0, 1, 2 and very close to -1.
In general, if you have two points (x, z) and (x, y), then the difference will obviously be (x, z - y). Determine this difference (at least visually and approximately) for any additional x coordinates that you'd like, and then smoothly connect the obtained points of the graph.
You need to define h since this is the first time it appears. Let h(x) = z(x) - y(x).
h(1) = log(1+1) - 1^3; the left-hand side is h(1), not h(x) for some indeterminate x.
h(1) is a number, it can't equal (1,-1), which is a pair of numbers.
log(2) - 1 is not -1.
Calculate h(0) and h(x) for x close to -1 (approximately).