• May 30th 2011, 12:32 AM
Barney

please i need help with this what would be the new set of points. i dont get it
• May 30th 2011, 01:04 AM
emakarov
You probably mean the segment (-1,2]. (Why do we have to guess?)

Draw both graphs. Note approximately their intersection points. The difference will be zero in these points. Determine where the difference w is positive and negative. Calculate the value (approximately) of w for x = 0, 1, 2 and very close to -1.

In general, if you have two points (x, z) and (x, y), then the difference will obviously be (x, z - y). Determine this difference (at least visually and approximately) for any additional x coordinates that you'd like, and then smoothly connect the obtained points of the graph.
• May 30th 2011, 01:21 AM
Barney
hi thankyou so is this what i do to get the points:
h(x)=loge(1+1)-1^3 = (1,-1)
h(x)=loge(2+1)-2^3 = (2,-6.90)
h(x)=loge(0.1+1)0.1^3 = (0.1,0.094)
• May 30th 2011, 01:35 AM
emakarov
You need to define h since this is the first time it appears. Let h(x) = z(x) - y(x).

h(1) = log(1+1) - 1^3; the left-hand side is h(1), not h(x) for some indeterminate x.

h(1) is a number, it can't equal (1,-1), which is a pair of numbers.

log(2) - 1 is not -1.

Calculate h(0) and h(x) for x close to -1 (approximately).
• May 30th 2011, 01:53 AM
Barney
h(x)=loge(1+1)-1^3 = (1,1.69)
h(x)=loge(2+1)-2^3 = (2,-6.90)
h(x)=loge(0.1+1)0.1^3 = (0.1,0.094)
h(0)=0
• May 30th 2011, 02:25 AM
emakarov
h(1) is still wrong.

Quote:

Originally Posted by emakarov
the left-hand side is h(1), not h(x) for some indeterminate x.

Quote:

Originally Posted by emakarov
h(1) is a number, it can't equal (1,-1), which is a pair of numbers.

Quote:

Originally Posted by emakarov
Calculate... h(x) for x close to -1 (approximately).

• May 30th 2011, 02:28 AM
Barney
oh is it -0.306
• May 30th 2011, 02:31 AM
emakarov
After you've done all of the above (note: I did not quote myself automatically), connect the points. You can calculate h(x) for other x's in the same way.
• May 30th 2011, 02:33 AM
Barney
thanks you gun
• May 30th 2011, 02:34 AM
emakarov
Also, the maximum will be approximately at x = 0.48.
• May 30th 2011, 02:39 AM
Barney
thankyou heaps