# Thread: Desperate and quick help needed

1. ## Desperate and quick help needed

Yes... I need a test that I have to submit relatively soon... I just can't figure these damn answers out. ):

Anyway.

Here are the two problems.

The temperature of surface of Mars is recored over a 24-hour period of time. The temperature varied from -30 degrees Celsius to -85 degrees Celsius. Find in Fahrenheit the warmest temperature during the 24-hour time period.

a.) -121 degrees
b.) -95.4 degrees
c.) -22 degrees
d.) -48.7

And...

A mining company digs ore from a mountain side. Three-sixteenths of the ore is pure copper. How much of this ore would need to be refined in order to yield 150 pounds of pure copper?

a.) 185 pounds
b.) 122 pounds
c.) 7200 pounds
d.) 800 pounds

Thanks guys. >_<

I just really need them soon. T_T; They're confusing. I'm not good with the C/F conversions... and blah. I just plain old don't understand the second.

Thanks again!

2. Originally Posted by Hallo
The temperature of surface of Mars is recored over a 24-hour period of time. The temperature varied from -30 degrees Celsius to -85 degrees Celsius. Find in Fahrenheit the warmest temperature during the 24-hour time period.

a.) -121 degrees
b.) -95.4 degrees
c.) -22 degrees
d.) -48.7
Use the formula conversion:
$\displaystyle \displaystyle T_f=\frac{9}{5}T_c+32$
where $\displaystyle T_f=$temperature in degrees Fahrenheit
$\displaystyle T_c=$remperature in degrees Celsius

A mining company digs ore from a mountain side. Three-sixteenths of the ore is pure copper. How much of this ore would need to be refined in order to yield 150 pounds of pure copper?

a.) 185 pounds
b.) 122 pounds
c.) 7200 pounds
d.) 800 pounds
Let $\displaystyle x$ be the quantity of ore.
Then you have to solve the equation
$\displaystyle \displaystyle\frac{3}{16}x=150$

3. Originally Posted by red_dog
Use the formula conversion:
$\displaystyle \displaystyle T_f=\frac{9}{5}T_c+32$
where $\displaystyle T_f=$temperature in degrees Fahrenheit
$\displaystyle T_c=$remperature in degrees Celsius

Let $\displaystyle x$ be the quantity of ore.
Then you have to solve the equation
$\displaystyle \displaystyle\frac{3}{16}x=150$
Thanks! But I know the equation for the first problem... and blah... I just don't know how to multiply by the fraction. ):

No idea how to work out the equation. Ahhh... I need to get better at this.

4. $\displaystyle \displaystyle T_f=\frac{9}{5}(-30)+32=-54+32=-22$

$\displaystyle \displaystyle\frac{3}{16}x=150\Rightarrow 3x=16\cdot 150\Rightarrow x=16\cdot 50=800$