Originally Posted by

**Jhevon** don't let the negatives bother you, just grind though. the negative in front of the d on the top is not being squared, so you can bring that out to the front. the one in front of the d at the bottom is being squared, so it will go away (that is, d^2 = (-d)^2), so you can pretty much forget about that one. otherwise, you need to know:

$\displaystyle \frac {x^a}{x^b} = x^{a - b}$

so you could write: $\displaystyle \frac {9c^7 w^{-4} (-d^2)}{15c^3w^6(-d)^2} = - \frac {9}{15} \cdot \frac {w^{-4}}{w^6} \cdot \frac {d^2}{d^2}$

where $\displaystyle \cdot$ means multiply.

Now continue