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Math Help - Simplifying an equation question

  1. #1
    Newbie
    Joined
    Mar 2011
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    Simplifying an equation question


    I'm really struggling with this one. I know the answer (it's in the back of the book) but I can't see how they get to the answer at all.

    <sorry, the display is wrong, the '2' '3' and '4''s are supposed to be powers>

    Simplify:

    a2b * ac2 / b2c
    2c 2b 2a

    This obviously equals:

    a2b * ac2 *2a
    2c 2b b2c

    The answer in the book is:

    b3
    ac

    and I don't get how the 'a' got to the bottom of this.

    My answer always ends up something like:

    a4
    b2
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  2. #2
    Super Member

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    Lexington, MA (USA)
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    Hello, PhilC!

    \text{Simplify: }\:\frac{a^2b}{2c}\cdot \frac{ac^2}{2b} \div \frac{b^2c}{2a}

    \text{This obviously equals: }\:\frac{a^2b}{2c}\cdot\frac{ac^2}{2b}\cdot\frac{2  a}{b^2c} . Right!

    \text{The answer in the book is: }\:\frac{b^3}{ac} . ??

    \text{and I don't get how the }a\text{ got to the bottom.} . Neither do I

    \text{My answer always ends up: }\:\frac{a^4}{b^2} . not quite

    \frac{a^2\rlap{/}b}{\rlap{/}2\rlap{/}c} \cdot\frac{a\rlap{/\!/}c^2}{2\rlap{/}b} \cdot \frac{\rlap{/}2a}{b^2\rlap{/}c} \;=\;\frac{a^4}{2b^2}

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  3. #3
    Newbie
    Joined
    Mar 2011
    Posts
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    Thanks, I did say "always ends up something like" and your answer is one of the ways it usually ends up.

    I thought I was going mad. I've double checked that I'm looking at the correct question / answer etc many times (if i have double checked many times at least I know it has to be an even number of times).

    Finally I can move onto the next section of the book.

    Thanks again!
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