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Math Help - A ladder 25 feet long...

  1. #1
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    A ladder 25 feet long...

    A ladder 25ft long leans against a vertical wall with its foot on level ground 7 ft from the base of the wall. If the foot is pulled away from the wall at the rate 2 ft/sec, express the distance (y ft) of the top of the ladder above the ground as a function of the time t sec in moving.

    Ans: y= 2(sqrt(144 - 7t - t^2)

    Can someone explain this one to me?
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  2. #2
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    try to calculate the value of y if the ladder is "x" feet away from the wall, the answer will be a function of X.

    Then use the fact that x = 7 + 2t
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