Hi,

Would someone kindly show and explain the proof by induction for 0! = 1

I would be very greatful if you could.

Thanks

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- May 18th 2011, 06:55 AMAbromavichProof by Induction for 0!
Hi,

Would someone kindly show and explain the proof by induction for 0! = 1

I would be very greatful if you could.

Thanks - May 18th 2011, 07:07 AMAckbeet
Your question makes no sense. A proof by induction, by definition, means you're trying to prove a statement that depends on some integer n. There is no such n in what you're trying to prove. To show that 0! = 1, I would use the generalized factorial function, the gamma function, and show that

But you'd need to know about the gamma function, which is defined in terms of an integral, and hence would be inappropriate for this forum. I can move this thread to Calculus, if you prefer, where the question would not be out of place. - May 18th 2011, 07:18 AMchisigma
A 'proof by induction' is consequence of the general property http://quicklatex.com/cache3/ql_0c64...1871046_l3.png in the particular case n=1...

Kind regards

- May 18th 2011, 10:06 AMchisigma
If we want to be 'rigorous' a precise definition of n! is necessary... in my opinion such precise definition is the following...

We call the n-th term of a sequence defined by the recursive relation...

(1)

... with the 'initial condition' , so that is true 'by definition'. Alternatively You can have as 'initial condition' an in this case 0! is defined writing the (1) as...

(2)

Kind regards

- May 18th 2011, 10:32 AMabhishekkgp