If y = t^m + t^-m , x = t + t^-1, show that

- (x^ 2 – 4) (dy/dx)^2 = m^2 (y^2 – 4)
this is what i have done:-

- (x^ 2 – 4) d^2y/dx^2 + x dy/dx – (m^2)y = 0

dy/dt = {(m)t^m-1} - {(m)t^-m-1}

dx/dt = [(t^2)- 1]/ t^2

then i calculated dy/dx

dy/dx = [{(m)t^m+1} - {(m)t^-m+1}] / (t^2) -1}

am i doing it right??