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Math Help - Solving for x

  1. #1
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    Solving for x

    Something has me confused :

    q^2 = u^2 + x^2 Make x the subject

    I got x= squareroot a^2 - u^2 as the answer.

    Having looked at the solution it's telling me the answer should be x = squareroot a^2 = u^2 ......is this their mistake or my mistake as usual?

    Thanks
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  2. #2
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by komodo View Post
    Something has me confused :

    q^2 = u^2 + x^2 Make x the subject

    I got x= squareroot a^2 - u^2 as the answer.

    Having looked at the solution it's telling me the answer should be x = squareroot a^2 = u^2 ......is this their mistake or my mistake as usual?

    Thanks
    The correct solution is x = \pm \sqrt{a^2 - u^2} as you say, though note the +/-. (I'm assuming the "q" in the original equation should have been an "a.") I am guessing the given solution is supposed to be this and the second = sign is meant to be a minus.

    -Dan
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  3. #3
    Senior Member abhishekkgp's Avatar
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    Quote Originally Posted by komodo View Post
    Something has me confused :

    q^2 = u^2 + x^2 Make x the subject

    I got x= squareroot a^2 - u^2 as the answer.

    Having looked at the solution it's telling me the answer should be x = squareroot a^2 = u^2 ......is this their mistake or my mistake as usual?

    Thanks
    x=\sqrt{a^2-u^2}, x=- \sqrt{a^2-u^2}
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  4. #4
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    Quote Originally Posted by topsquark View Post
    The correct solution is x = \pm \sqrt{a^2 - u^2} as you say, though note the +/-. (I'm assuming the "q" in the original equation should have been an "a.") I am guessing the given solution is supposed to be this and the second = sign is meant to be a minus.

    -Dan
    Yeah the q should have been an a.....so I'm guessing the = sign is just a typo on their behalf and it should have been a minus sign.

    Quote Originally Posted by abhishekkgp View Post
    x=\sqrt{a^2-u^2}, x=- \sqrt{a^2-u^2}
    Thanks
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