Thread: solve for pronumeral

my problem is this log 2y/3=3

i think to make like this y/3=2^3
we get y/3=8
then to get for y we have y=8x3 =24

therefore y =24

Is this correct ??

This is the way I'd do it:
2y/3 = 3
2y = 3*3
2y = 9
y = 9/2
y = 4.5

[even for the log function

Originally Posted by gregorio

my problem is this log 2y/3=3

i think to make like this y/3=2^3
we get y/3=8
then to get for y we have y=8x3 =24

therefore y =24

Is this correct ??

Yes, that's correct.

So, if y=24,
Log(2)[y/3] = 3
Log(2)[24/3] =? 3
Log(2)[8] =? 3
Log(2)[2^3] =? 3
3Log(2)[2] =? 3
3 =? 3
Yes, so, OK.
which is

Hi ticbol, so my answer is correct because someone else reply and tell me different ?? I am not english mother tongue and my practice papers are in english so sometimes is difficult to understand for me. thank you for help, you already help me many times, however i have many mre questions stil !!!!

ticbol would be correct with this one, not me

Originally Posted by gregorio

Hi ticbol, so my answer is correct because someone else reply and tell me different ?? I am not english mother tongue and my practice papers are in english so sometimes is difficult to understand for me. thank you for help, you already help me many times, however i have many mre questions stil !!!!

Yes, there are sometimes different answers to only one question by the many "answerers" here. Which one is correct? You have to check their answers against the original equation/inequality/relation in your question if that is possible. If not, I cannot say how you choose the correct one.

It is okay if you are not yet very good at English. Math is not a language---er, sorry about that---does not depend much on English to be understood. Well, except in word problems.

Post them questions, one at a time. Let us---we here---solve them.