I need help with the steps and solving for an equation of the line containing the given point and perpendicular to the line:

(5, -2); 9x + 8y =3

I can find the slope (-8/9x?)... I just can't figure out the rest(Headbang)

- May 12th 2011, 09:28 AMjay1An equation of the line containing the given point and perpendicular to the line
I need help with the steps and solving for an equation of the line containing the given point and perpendicular to the line:

(5, -2); 9x + 8y =3

I can find the slope (-8/9x?)... I just can't figure out the rest(Headbang) - May 12th 2011, 09:33 AMQuacky
The gradient of the normal to the line will be the negative reciprocal of the original gradient. That is, if your gradient is , the gradient of the normal will be . Then, once you've found the gradient, substitute it, along with your point, into or to find the equation.

- May 12th 2011, 09:48 AMmasters
- May 12th 2011, 11:18 AMPlato
- May 12th 2011, 12:18 PMWilmer
You've got a point and the slope; go find out:

Straight-Line Equations: Point-Slope Form