Hello
I am new in this forum
I try to calculate
{-10}^{ 2.6}
using the calculator I get an error
but i write that way
{-10}^{ 2.6} = {-10}^{ 2+ 6/10} = {-10}^{ 2+ 3/5} = {-10}^{2 } * {-10}^{3/5 }
= 100 * {{-10}^{ 3} }^{1/ 5} = 100*{-1000}^{ 1/5} \approx -398.107
i don't know if it's correct
so for {-10}^{ 2.8} i get 630.957344480193
Thanks in advance
Hi shayw,
I assume you mean the power of a negative integer. You can simplify calculations by factoring the negative integer
-10^2.8 =(-1)^2.8 * 10^2.8
10^2.8 = 630.957
(-1)^2.8 =(-1)^2 *(-1)^.8=1*1 answer is positive
If the original problem was(-10)^2.7
(-10)^2.7 =(-1)^2.7 * 10^2.7
= (-1)^2 *(-1)^.5 * (-1)^.2 * 10^2.7
= 1*-1*1=-1
answer will be negative
bjh
1. You know that
(In German the number w is called exponent of the root. Maybe that's the reason why I used a wrong expression)
2. Re-write an exponent as a completely simplified fraction. Then the denominator of this fraction indicates if it is an odd or even root.
Dr. Steve didn't say it would help determine if such a root was real or not- only that it could be used to find the root if it existed. If is a sequence of rational numbers converging to then for any positive real number, X, is defined as the limit of the sequence . In general, negative real numbers to an irrational power are not defined.