factoring a basic quadratic equation

Hello - this is two part question. First, can someone please help me factor this equation, or is this even factorable?

(4x^2+4x+2)

I've tried factoring this into either (2x-1)(2x-2) or (4x-1)(x-2), but as you can see I can't seem to find a number that will add up to 4x.

Secondly, once this is factorable, can someone show me how to solve this equation algebraically:

(4x^2+4x+2)+(3-7x)-(5-3x)

I know that I can substitute (using Princeton Review method to find answer) let's say 2 for x's and get the following, but would like to understand how this can be set up and solved for x:

(16+8+2)+(3-14)-(5-6)=

26-11+1 = 16

Many thanks