Algebraic Fractions

**JanoD** · May 9th 2011, 03:24 AM

I'm working from an algebra workbook and one of the questions has me stumped.

Picture: First one is the correct answer, and the second one is the one I thought it would be.

Why am I wrong?

**Plato** · May 9th 2011, 03:35 AM

\hat{\jmath}

Originally Posted by JanoD

I'm working from an algebra workbook and one of the questions has me stumped.
Picture: First one is the correct answer, and the second one is the one I thought it would be.

Why am I wrong?

Because $\frac{3-2x}{2}=\frac{3}{2}-\frac{2x}{2}.$

**bugatti79** · May 9th 2011, 03:36 AM

Originally Posted by JanoD

I'm working from an algebra workbook and one of the questions has me stumped.

Picture: First one is the correct answer, and the second one is the one I thought it would be.

Why am I wrong?

You must use this rule for algebraic substraction

$\displaystyle \frac{a-bc}{b}=\frac{a}{b}-\frac{bc}{b}=\frac{a}{b}-c$

**JanoD** · May 9th 2011, 03:39 AM

Thanks a load! Wasn't expecting a reply so quickly.

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